If a carrier wave C(t) = A sin omega_c t is a | vedclass

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(C) The standard equation for an amplitude modulated wave is given by $C_m(t) = A_c(1 + \mu \sin \omega_m t) \sin \omega_c t$,where $\mu$ is the modul

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$C_m(t) = A(1 + \sin \omega_m t) \sin \omega_c t$ and $1$

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(C) The standard equation for an amplitude modulated wave is given by $C_m(t) = A_c(1 + \mu \sin \omega_m t) \sin \omega_c t$,where $\mu$ is the modulation index.Given the carrier wave $C(t) = A \sin \omega_c t$ and the modulating signal $m(t) = A \sin \omega_m t$,the amplitude of the carrier is $A_c = A$ and the amplitude of the modulating signal is $A_m = A$.The modulation index $\mu$ is defined as $\mu = \frac{A_m}{A_c} = \frac{A}{A} = 1$.Substituting $\mu = 1$ and $A_c = A$ into the general equation,we get $C_m(t) = A(1 + 1 \cdot \sin \omega_m t) \sin \omega_c t = A(1 + \sin \omega_m t) \sin \omega_c t$.Thus,the modulated signal is $C_m(t) = A(1 + \sin \omega_m t) \sin \omega_c t$ and the modulation index is $1$.

If a carrier wave $C(t) = A \sin \omega_c t$ is amplitude modulated by a modulating signal $m(t) = A \sin \omega_m t$,then the equation of the modulated signal $[C_m(t)]$ and its modulation index are respectively:

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